2X^2+y^2+4y+10=0

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Solution for 2X^2+y^2+4y+10=0 equation: 



2X^2+X^2+4X+10=0

We add all the numbers together, and all the variables

3X^2+4X+10=0

a = 3; b = 4; c = +10;
Δ = b2-4ac
Δ = 42-4·3·10
Δ = -104
Delta is less than zero, so there is no solution for the equation

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